pakai cara ya.......
Jawaban:
~Bangun ruang~
______________
3.V = kacang rebus
= kacang rebus × 1/3 × π × r × r × t
= 2/3 × 1/3 × 22/7 × 7 × 7 × 27
= 924 cm³
4.r = √(3 × v) ÷ (π × t)
= √(3 × 16632)÷ (22/7 × 36)
= √[49896 ÷ 792/7]
= √[49896 × 7/792]
= √441
= 21 cm
5. v tabung di luar kerucut
= 2/3 × 1/4 × π × d × d × t
= 2/3 × 1/4 × 22/7 × 14 × 14 × 30
= 3080 cm³
3]
r = 7 cm
kacang rebus = 2/3 bagian
t = 27 cm
V kacang rebus
= kacang rebus × 1/3 × phi × r × r × t
= 2/3 × 1/3 × 22/7 × 7 × 7 × 27
= 924 cm^3
4]
v = 16632 cm^3
t = 36 cm
phi = 22/7
r = V[(3 × v)/(phi × t)]
r = V[(3 × 16632)/(22/7 × 36)]
r = V[49896/(792/7)]
r = V[49896 × 7/792]
r = V441
r = 21 cm
5]
d = 14 cm
t = 30 cm
v tabung di luar kerucut
= 2/3 × 1/4 × phi × d × d × t
= 2/3 × 1/4 × 22/7 × 14 × 14 × 30
= 3080 cm^3
[answer.2.content]
